**Misconception about the omnipotence of God**

Since misconceptions are a type of trash, we should not let them accumulate in our mind.

One of such misconceptions is the misconception about the omnipotence of God.

Though the capability of the entity known as God, to have been able to create the first male ancestor and first female ancestor of the human species speaks volumes about His omnipotence as well as His omniscience — I leave it on you to decide whether we should regard His inability to prevent the loss of the electromagnetic rays emitted by all stars of the universe, which go beyond the boundaries of the universe, being incurred right from the day of the evolution of the universe as a slur on His omnipotence or not.

It would have not mattered much had the quantum of the waves that go beyond the boundaries of the universe been only a miniscule.

But it makes a big difference because, according to my calculations, as much as **62.69 x 10⁶⁰ **KW of energy produced by all stars has already drained since the evolution of the universe.

**If God would have been omnipotent, should it have not occurred to Him to do something to avoid such rampant wastage of energy?**

*Though it does not seem to have been possible to have saved such rays — would it have not been better if such energy could have been, somehow, salvaged?*

*Does it not imply that it may have not been possible even for God to have salvaged such energy?*

BE IT SO, SHOULD WE NOT TAKE IT FOR GRANTED THAT GOD MAY NOT BE AN OMNIPOTENT ENTITY?

Anyway, should you be interested to know how I calculated the loss incurred by the universe by way of losing such rays — I calculated it in the following manner.

**The manner in which I calculated the loss of the energy being incurred**

Since we know that Sun generates **3.8 x 10²⁶ W of energy **per second, it works out to generation of **11.98 x 10²⁷ KW **of energy** **per year.

After calculating how much energy is produced by the Sun per year, we may calculate what percentage of the energy produced by it falls on the Earth, based on the following diagram.

As shown in this diagram, the rays produced by the Sun spread out in all directions.

Since the average distance of the Earth from the Sun is about **150 million km**, the surface area of a celestial sphere of such radius works out to “4 π x 22500 x 10¹² sq km”, which turns out to be **28.286 x 10¹⁶ sq km**.

Likewise, since the average radius of the Earth is** 6731 km**, the surface area of the Earth exposed to the Sun is 2 π x 45.3 x 10⁶ sq km, which turns out to be **28.47 x 10⁷ sq km**.

If we divide **28.47 x 10⁷** by **28.286 x 10¹⁶** and multiply the dividend by **100**, we can calculate the percentage of the rays emitted by the Sun intercepted by the Earth.

*This percentage works out to only 0.000,000,1 — which implies that hardly 0.000,000,1 per cent of the rays produced by the Sun fall on the Earth.*

Just think — what percentage of the remaining 99.9999999% of the rays may b1e getting intercepted by other planets of the Sun and any other celestial bodies of the universe falling on their way, during their journey up to the **boundaries of the universe**.

*Though we are not sure about the overall shape of the universe, we may consider the point beyond which it ceases to exist in any direction as its edge in that direction.*

**Let us assume that 2% of the power-output of the Sun may be getting intercepted by the other planets of the Sun as well as all celestial bodies of the universe, that may intercept its rays on their journey up to the edge of the universe.**

Though the power output of some stars of the universe is less than the power output of our star and, the power output of some stars of the universe is more than the power output of our star — since the Sun happens to be a star of an average size in our galaxy, let us assume that it may be an average-sized star of even the entire universe and if so, we may also assume that the average power output per star may be the same as the power output of the Sun and, calculate the power output of all stars that reaches the boundaries of the universe per year, as follows.

Since there are 2oo sextillion stars of various sizes, that is — 200 x 10²¹ stars in the whole** **space, total power output of all stars per year may be calculated as follows.

Total power output of all stars per year = (11.98 x 10²⁷) x (200 x 10²¹), which works out to **23.96 x 10⁵⁰ KW per year**.

Let us assume that not only 2% of the rays produced by the Sun, may be getting intercepted by the other planets of the Sun as well as all the celestial bodies that may intercept them, during their journey up to the edges of the universe — 2% 0f the energy emitted by all stars of the universe, may be getting intercepted by the celestial bodies falling on the way of their rays also by the time they reach the edges of the universe.

Based on this assumption, we may calculate the quantity of the energy of all stars of the universe reaching the boundary of the universe, as follows.

**The quantity of the energy of all stars of the universe reaching the boundary of the universe per year = 0.98 x 23.96 x 10⁵⁰, which works out to 23.48 x 10⁵⁰ KW.**

*Since the age of the universe is about **26.7 billion years**, we may calculate the total power-output of all stars put together, that has reached the boundary of the universe since the evolution of the universe until now, as follows.*

The energy emitted by all stars put together, that has reached the edge of the universe since the evolution of the universe until now = 23.48 x 10⁵⁰ x 26.7 x 10⁹, which works out to **62.69 x 10⁶⁰ KW**.

*Though until now, we don’t know whether the electromagnetic rays which reach the boundary of the universe get recycled or not, don’t you think — it should be possible for the astronomers to find out whether such energy is getting recycled or not?*

A question arises — does all talk about omnipotence of God make any sense till we do not get the final word about it, from the astronomers?